You should get three compilation errors indicating that variables x, y and z "might not have been initialized" and therefore their values cannot be displayed by the System.out.println statements.
This is an example of a situation where Java does not initialize variables to a default value. To correct these errors, you need to explicitly assign an initial value to each variable (as in the next task).
x = 23; y = 333; z = 99;
Note that it is important to use lower case names for x, y and z, as that is how they have been declared (since Java is case-sensitive).
We could also have carried out declaration and initialization in one statement as follows:
int x = 23; int y = 333; int z = 99;
The output should be:
After initialization: x contains 23 y contains 333 z contains 99
x = x + 12;
y = y - 100;
z = x * y;
System.out.println("After further calculations:");
System.out.println("x contains " + x );
System.out.println("y contains " + y );
System.out.println("z contains " + z );
The output should be:
After initialization: x contains 23 y contains 333 z contains 99 After further calculations: x contains 35 y contains 233 z contains 8155